We can rewrite an equation in slope-intercept form (y=mx+b) to be in standard form (Ax+By=C) instead.
There are several orders in which you can accomplish the steps needed to change from point-slope to general form, but basically: subtract m(x-x1) from both sides: y - y1 -m(x - x1)= 0. distribute m, yielding y - y1 -mx +mx1 = 0. combine the constants y1 and mx1. Rearrange the order so you have -mx +y +(mx1-y1)=0.
But we could find a slope since we're given the two points. And we could use this formula m is equalMoreBut we could find a slope since we're given the two points. And we could use this formula m is equal to Y2 over y1. I mean Y2 minus y1 over X2 minus X1.
To find the slope using a general or standard form equation, use the slope formula: m=-A/B where A and B are integer variables found in the equation. The m is the slope.
What is the point slope form equation of a line passing through the origin with slope m? The equation of a line in point slope form is y – y1 = m(x – x1). Therefore, the equation of a line passing through the origin with slope m is: y – 0 = m(x = 0), i.e. y = mx.
Thus, to convert to point-slope form, first convert to slope-intercept form, then move the constant term b to the left side of the equation (or isolate x and then divide by the y coefficient). Example: Convert 3x = 4y + 8 to point-slope form.