What is the point slope form equation of a line passing through the origin with slope m? The equation of a line in point slope form is y – y1 = m(x – x1). Therefore, the equation of a line passing through the origin with slope m is: y – 0 = m(x = 0), i.e. y = mx.
To find the slope using a general or standard form equation, use the slope formula: m=-A/B where A and B are integer variables found in the equation. The m is the slope.
There are several orders in which you can accomplish the steps needed to change from point-slope to general form, but basically: subtract m(x-x1) from both sides: y - y1 -m(x - x1)= 0. distribute m, yielding y - y1 -mx +mx1 = 0. combine the constants y1 and mx1. Rearrange the order so you have -mx +y +(mx1-y1)=0.
We can rewrite an equation in slope-intercept form (y=mx+b) to be in standard form (Ax+By=C) instead.
Negative 12. And then you can simply subtract 6. And then change all of the sides. So hopefully byMoreNegative 12. And then you can simply subtract 6. And then change all of the sides. So hopefully by now you can take an equation that's written in point slope form.
Since we have a graph, we can find the slope using rise over run, 6 2 = 3 and the y-intercept is (0, 6). The equation of the line, in slope-intercept form, is y = 3 x + 6 . To change the equation to general (standard) form, subtract the x-term to move it over to the other side.
A higher positive slope means a steeper upward tilt to the curve, which you can see at higher output levels. A negative slope that is larger in absolute value (that is, more negative) means a steeper downward tilt to the line. A slope of zero is a horizontal line. A vertical line has an infinite slope.
How do I convert slope intercept form to standard form? Move all the terms to one side of the equality sign. Remember about changing the signs! Rearrange the equation so that the term with x is first, then the term with y , and then the intercept last. We now have mx - y + b = 0 and… this is already the standard form!