Point-slope appears in the form y-y1= m (x-x1). Take an example: y-5=15(x-2). This function has a slope of 15 and includes the point (2,5). To convert it to standard form (y=mx+b), you simply distribute the 15 to the terms in parentheses and then add 5 to both sides to isolate y.
Point-slope is the general form y-y₁=m(x-x₁) for linear equations. It emphasizes the slope of the line and a point on the line (that is not the y-intercept). We can rewrite an equation in point-slope form to be in slope-intercept form y=mx+b, to highlight the same line's slope and y-intercept.
Since we have a graph, we can find the slope using rise over run, 6 2 = 3 and the y-intercept is (0, 6). The equation of the line, in slope-intercept form, is y = 3 x + 6 . To change the equation to general (standard) form, subtract the x-term to move it over to the other side.
The general form of the equation of a line ? ? + ? ? + ? = 0 is closely related to its standard form: ? ? + ? ? = ? , where ? , ? , and ? are integers and ? is nonnegative. We can convert the standard form into general form by subtracting the constant ? from both sides of the equation.
Given two points on a line, we can write an equation for that line by finding the slope between those points, then solving for the y-intercept in the slope-intercept equation y=mx+b.
In general form they would be the same. So you can use whichever you prefer. So I'm going to say yMoreIn general form they would be the same. So you can use whichever you prefer. So I'm going to say y minus 6. Equals now my slope is up here negative eight over three times x minus X1 was 1..
If given two points, first find the slope (m) of the line that contains the points. Then write an equation in slope-intercept form (y=mx+b) and substitute in the x and y values for one of the points to find the y-intercept (b). Then convert to standard form (Ax+By=C) by subtracting the (mx) term from each side.
In general form they would be the same. So you can use whichever you prefer. So I'm going to say yMoreIn general form they would be the same. So you can use whichever you prefer. So I'm going to say y minus 6. Equals now my slope is up here negative eight over three times x minus X1 was 1..
Since we have a graph, we can find the slope using rise over run, 6 2 = 3 and the y-intercept is (0, 6). The equation of the line, in slope-intercept form, is y = 3 x + 6 . To change the equation to general (standard) form, subtract the x-term to move it over to the other side.
Answer and Explanation: To change slope-intercept form to standard form, use inverse operations and properties of equality to write the equation in the form A x + B y = C , where and are integers, is positive, and at least an or is present.