We can rewrite an equation in slope-intercept form (y=mx+b) to be in standard form (Ax+By=C) instead.
How do you find the slope in general form? To find the slope using a general or standard form equation, use the slope formula: m=-A/B where A and B are integer variables found in the equation. The m is the slope.
First you want to move the Ax to the opposite side of the equation, by either adding or subtracting it. At this point your equation will be set up By = -Ax + C. Then you want to divide the B from the By and the rest of the equation. Therefore you will have y = - Ax/B + C/B.
To find the slope using a general or standard form equation, use the slope formula: m=-A/B where A and B are integer variables found in the equation. The m is the slope.
Thus, to convert to point-slope form, first convert to slope-intercept form, then move the constant term b to the left side of the equation (or isolate x and then divide by the y coefficient). Example: Convert 3x = 4y + 8 to point-slope form.
Thus, to convert to point-slope form, first convert to slope-intercept form, then move the constant term b to the left side of the equation (or isolate x and then divide by the y coefficient). Example: Convert 3x = 4y + 8 to point-slope form.
How do I convert standard form to slope intercept form? Make sure that B is not equal to zero — if it is, the slope-intercept form does not exist. Rewrite your equation as By = -Ax - C . Divide both sides by B . We get y = -(A/B)x - C/B . We've found the slope-intercept form!
What is the point slope form equation of a line passing through the origin with slope m? The equation of a line in point slope form is y – y1 = m(x – x1). Therefore, the equation of a line passing through the origin with slope m is: y – 0 = m(x = 0), i.e. y = mx.