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The equation of a straight line joining two points (x1, y1) and (x2, y2) is given by two-point form y - y1 = (x - x1)(y2 - y1)/(x2 - x1). Alternatively, we can first find its slope using m = (y2 - y1)/(x2 - x1) and then use the point-slope form y - y1 = m (x - x1).
In general form they would be the same. So you can use whichever you prefer. So I'm going to say yMoreIn general form they would be the same. So you can use whichever you prefer. So I'm going to say y minus 6. Equals now my slope is up here negative eight over three times x minus X1 was 1..
Answer so this is the equation. In point slope. Form. But now let's get the answer in slopeMoreAnswer so this is the equation. In point slope. Form. But now let's get the answer in slope intercept. Form. So let's distribute the two. It's going to be 2X. And then 2 -5 that's -10.
The general form ax+by+c=0 is one of the many different forms you can write linear functions in. Other ones include the slope intercept form y=mx+b or slope-point form.
The equation of a straight line is y=mx+c y = m x + c m is the gradient and c is the height at which the line crosses the y -axis, also known as the y -intercept.
In general form they would be the same. So you can use whichever you prefer. So I'm going to say yMoreIn general form they would be the same. So you can use whichever you prefer. So I'm going to say y minus 6. Equals now my slope is up here negative eight over three times x minus X1 was 1..
One this is going to help us to find the equation of the line. So all we need is the slope m. AndMoreOne this is going to help us to find the equation of the line. So all we need is the slope m. And just one of the two. Points. You could use x1 y1 or x2 y2.
So let's go ahead and plug the values in into this formula. So let's replace y2f9. And y1 with oneMoreSo let's go ahead and plug the values in into this formula. So let's replace y2f9. And y1 with one x2 is two and let's replace x1 with negative two. So we have nine minus one which is eight.
If given two points, first find the slope (m) of the line that contains the points. Then write an equation in slope-intercept form (y=mx+b) and substitute in the x and y values for one of the points to find the y-intercept (b). Then convert to standard form (Ax+By=C) by subtracting the (mx) term from each side.
In general form they would be the same. So you can use whichever you prefer. So I'm going to say yMoreIn general form they would be the same. So you can use whichever you prefer. So I'm going to say y minus 6. Equals now my slope is up here negative eight over three times x minus X1 was 1..