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Sodium borohydride will reduce ketone to alcohol. It will not reduce amide group and C=C double bond.
Nevertheless, an alcohol, often methanol or ethanol, is generally the solvent of choice for sodium borohydride reductions of ketones and aldehydes.
NaBH4 is not able to reduce isolated C=C bond. But, NaBH4 reduces the double bond present in an enal (a conjugated aldehyde). After the reaction C=C bond is gone and left aldehyde is reduced to alcohol in next step by NaBH4.
Sodium borohydride will reduce aldehydes to primary alcohols and ketones to secondary alcohols. This proceeds via a two-step mechanism consisting of 1) nucleophilic addition, followed by 2) protonation.
Sodium borohydride reduces disulfides to thiols, which can then be used to reduce nitro groups. Based on the redox properties of 1,2-dithiolane, lipoamide (17) was used for the selective reduction of monosubstituted nitrobenzenes to the corresponding anilines.