The slope intercept formula y = mx + b is used when you know the slope of the line to be examined and the point given is also the y intercept (0, b). In the formula, b represents the y value of the y intercept point.
What is the point slope form equation of a line passing through the origin with slope m? The equation of a line in point slope form is y – y1 = m(x – x1). Therefore, the equation of a line passing through the origin with slope m is: y – 0 = m(x = 0), i.e. y = mx.
There are several orders in which you can accomplish the steps needed to change from point-slope to general form, but basically: subtract m(x-x1) from both sides: y - y1 -m(x - x1)= 0. distribute m, yielding y - y1 -mx +mx1 = 0. combine the constants y1 and mx1. Rearrange the order so you have -mx +y +(mx1-y1)=0.
General form is Ax + By - C = 0, where A, B, and C are integers with a GCD of 1. There are several orders in which you can accomplish the steps needed to change from point-slope to general form, but basically: subtract m(x-x1) from both sides: y - y1 -m(x - x1)= 0. distribute m, yielding y - y1 -mx +mx1 = 0.
If the equation is in the form y= mx+b, the slope is m and the y-intercept is b. If the line is in the form ax+by= c, then the slope is -a/b and the y-intercept is c/b.
Form. Because from slope intercept form we know it's y equals MX plus b so whatever the M value isMoreForm. Because from slope intercept form we know it's y equals MX plus b so whatever the M value is that's the slope. Okay so basically what that means is we're going to isolate y.
To find the slope using a general or standard form equation, use the slope formula: m=-A/B where A and B are integer variables found in the equation. The m is the slope.
You need the equation of the line. If the equation is in the form y= mx+b, the slope is m and the y-intercept is b. If the line is in the form ax+by= c, then the slope is -a/b and the y-intercept is c/b.