Order Setting Bond With Resonance Structures
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FAQ
Bond order = [(Bonding molecules' number of electrons) ? (Antibonding molecules' number of electrons)]/2. Where, Nb is that the number of bonding electrons. Na is that the number of antibonding electrons.
Aso Bond order of a molecule can be calculated by using bonding and ant bonding electrons in case of resonance, it can be calculated by dividing total number of bonds involved resonance by total number of resonating structures.
Aso Bond order of a molecule can be calculated by using bonding and ant bonding electrons in case of resonance, it can be calculated by dividing total number of bonds involved resonance by total number of resonating structures.
Bond order (B.O.) is defined as one-half the difference between the number of electrons present in the bonding and the anti-bonding orbitals. Bond order (B.O) = ( Number of bonding electrons - Number of the anti-bonding electron) Bond order = (Nb- Na)
The resonance hybrid has two identical N-O bonds. They share a double bond and a single bond between them, so the average bond order is 1.5. We would predict that the N-O bond length should be halfway between a single bond and a double bond.
