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Ing to the molecular orbital configuration, there are 10 bonding and 6 nonbonding electrons in the orbitals. As a result, the bond order of =1 / 2[10-6]=1 / 2(4)=2 is 2.
Bond order (B.O.) is defined as one-half the difference between the number of electrons present in the bonding and the anti-bonding orbitals. Bond order (B.O) = ( Number of bonding electrons - Number of the anti-bonding electron) Bond order = (Nb- Na)
Bond order (B.O.) is defined as one-half the difference between the number of electrons present in the bonding and the anti-bonding orbitals. Bond order (B.O) = ( Number of bonding electrons - Number of the anti-bonding electron) Bond order = (Nb- Na)
The bond length of O-O in H2O2 is 147.5 pm, in O3 is 128 pm and in O2 it is 121 pm , so the correct order is O2<O3<H2O2.