Second Motion Examination With Derivation
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FAQ
To derive the equation s = ut + 1/2at², you can start from the definitions of average velocity and acceleration. By rearranging the terms and applying the concept of uniform acceleration, the equation can be formulated step-by-step. This detailed process is fundamental in a second motion examination with derivation.
To derive v² = u² + 2as, start with the definitions of initial velocity (u), final velocity (v), and constant acceleration (a). This equation illustrates how the change in velocity relates to the distance traveled through acceleration. This derivation encapsulates important principles in the second motion examination with derivation.
To derive the equation s = ut + 1/2 at², start with the definitions of displacement (s), initial velocity (u), and acceleration (a). Recognize that displacement can be represented as the sum of initial velocity multiplied by time plus the additional distance from acceleration over time. This derivation illustrates key principles in the second motion examination with derivation.
BC = BD + DC. Therefore, v = BD + DC. v = BD + OA (since DC = OA) Finally, v = BD + u (since OA = u) (Equation 1) Now, since the slope of a velocity-time graph is equal to acceleration a. ... a = slope of line AB. a = BD/AD. Since AD = AC = t, the above equation becomes: BD = at (Equation 2)
Distance covered in nth second : S = ut + 1/2 at 2 is the distance covered by a body in t s. [distance covered by a body along a straight line in n second.
We know that: v = u + at. substituting this value of ?v? in eq.(1), we get. s=(u+u+at)2×t. Or, ?s=(2u+at)2×t. Or, ?s=(2ut+at2)2.
EXPLANATION:? The second equation of motion gives the position-time relation, i.e. s = ut + (1/2) at2. Here, v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.
Hence, the formula for distance travelled in nth second is given by, Sn = u + a (n ? ½).
