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The bond order of N2 is 3.
Hence, option (D) is correct., N 2 > N 2 + > N 2 - > N 2 2 - is the correct stability order for and its given ions.
But first, we look at the diagram of molecular orbitals for N2 (the bond order for the nitrogen molecule is 3).
Diatomic nitrogen has a bond order of three and is a diamagnetic molecule. Because two electrons are now added in the 3 MO, the bond order for dinitrogen is $ 1{{\sigma }_{g}}^{2}1{{\sigma }_{u}}^{2}2{{\sigma }_{g}}^{2}2{{\sigma }_{u}}^{2}1{{\pi }_{u}}^{4}3{{\sigma }_{g}}^{2} $ .
In N2?Bondorder=10?42=3?N?N. In O2?Bondorder=10?62=2?O?O. Bondorder=9?62=32=1.5.