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45 A 10 N force is applied to a 6 kg box, as shown below. 6 kg10 NAssume the system is frictionless. a. Determine the weight of the box in newtons. Show your calculations and include units in your.

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  1. Click ‘Get Form’ button to access the document and open it in the form editor.
  2. In the first section, calculate the weight of the box by using the formula: weight = mass × gravity. Since the mass of the box is given as 6 kg, multiply it by the acceleration due to gravity (9.81 m/s²) to obtain the weight in newtons. Remember to show your calculations and include the appropriate units in your answer.
  3. Next, move to the force diagram section. You will need to create a visual representation of the box and the forces acting on it. Be sure to label each force and depict their relative magnitudes accurately.
  4. In the following section, determine the acceleration of the box using Newton's second law of motion. The formula is: acceleration = net force / mass. You can substitute the net force (10 N) and the mass (6 kg) into this formula. Again, show all calculations and include the units in your answer.
  5. Finally, in the last section, discuss one modification to the system that would allow it to achieve the same acceleration when friction is present. Provide a thoughtful and clear explanation of your reasoning.
  6. Once all sections of the form are completed, review your entries for accuracy. After verifying your information, save your changes, and you can choose to download, print, or share the completed form as needed.

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1 Answer. Explanation: Force (F) = 10 N and acceleration (a) = 1 m/s2. Mass (m) = F/a = 10/1 = 10 kg.

a=2m/s2.

when a force of 10N applied on a body for 5 second then, change in momentum of body will be 50Ns. Let p=change in momentum, F= net force, and t = time over which net force F is applied. p=integral(F) dt, which if F is constant, is just p=F*t.

F=10N=the net force acting on the block; m=5kg=mass of the block; From Newton's 2nd law in (1), a=F/m=(10/5)N/kg=2m/s^2=acceleration produced by the net force.

The force applied is 10 N, the mass is 5 kg, and the acceleration is 1.5 m/s^2. Using the equation F_net = ma, we can rearrange it to solve for the force of friction. Therefore, the magnitude of the force of friction acting on the mass is 2.5 N.

= 10 5 = 2 m / s 2. A force of 10 N acts on a body of mass 5 kg.

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© Copyright 1997-2025
airSlate Legal Forms, Inc.
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Form Packages
Adoption
Bankruptcy
Contractors
Divorce
Home Sales
Employment
Identity Theft
Incorporation
Landlord Tenant
Living Trust
Name Change
Personal Planning
Small Business
Wills & Estates
Packages A-Z
Form Categories
Affidavits
Bankruptcy
Bill of Sale
Corporate - LLC
Divorce
Employment
Identity Theft
Internet Technology
Landlord Tenant
Living Wills
Name Change
Power of Attorney
Real Estate
Small Estates
Wills
All Forms
Forms A-Z
Form Library
Customer Service
Terms of Service
Privacy Notice
Legal Hub
Content Takedown Policy
Bug Bounty Program
About Us
Blog
Affiliates
Contact Us
Delete My Account
Site Map
Industries
Forms in Spanish
Localized Forms
State-specific Forms
Forms Kit
Legal Guides
Real Estate Handbook
All Guides
Prepared for You
Notarize
Incorporation services
Our Customers
For Consumers
For Small Business
For Attorneys
Our Sites
US Legal Forms
USLegal
FormsPass
pdfFiller
signNow
airSlate WorkFlow
DocHub
Instapage
Social Media
Call us now toll free:
+1 833 426 79 33
As seen in:
  • USA Today logo picture
  • CBC News logo picture
  • LA Times logo picture
  • The Washington Post logo picture
  • AP logo picture
  • Forbes logo picture
© Copyright 1997-2025
airSlate Legal Forms, Inc.
3720 Flowood Dr, Flowood, Mississippi 39232