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Moles of ALO3 = (19.67 moles of M0,0) × (4 moles of ALO3 / 8 moles of Al) Moles of ALO3 = 9.835 moles. Therefore, 3580 g of manganomanganic oxide (M0,0) will produce approximately 9.835 moles of aluminum oxide (ALO3).
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